Answer
Real numbers greater than or equal to $-2$.
Work Step by Step
$\sqrt {x+2}$
The square root of a negative has no solution in the set of the real numbers. It is necessary that:
$x+2\geq0$
$x\geq-2$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - Review Exercises - Page 64: 93
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