Answer
$x=3.47$ or $x=0.63$
Work Step by Step
We are given:
$x^{2}-4.1x+2.2=0$
We solve using the quadratic formula ($a=1,\ b=-4.1,\ c=2.2$):
$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$
$x=\frac{-(-4.1)\pm\sqrt{(-4.1)^{2}-4*1*2.2}}{2*1}$
$x=\frac{4.1\pm\sqrt{16.81-8.8}}{2}$
$x=\frac{4.1\pm\sqrt{8.01}}{2}$
$x=3.47$ or $x=0.63$
