College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.2 - Quadratic Equations - 1.2 Assess Your Understanding - Page 102: 98

Answer

$25$ ft.

Work Step by Step

The radius must equal half the diagonal of the square. If the square has side x, the diagonal is $d=x\sqrt{2}$. this follows from the Pythagorean relation when we observe the triangle with sides $d, x, x.$ $d^{2}=x^{2}+x^{2}$ $d^{2}=2x^{2}$ Given that $x^{2}=1250$ sq.ft., it follows that $d^{2}=2500$ sq.ft. Taking the square root, as d can be be positive only, $d=50$ ft Half of that is the wanted radius, $25$ ft.
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