Chapter 1 - Section 1.2 - Quadratic Equations - 1.2 Assess Your Understanding - Page 102: 71

$\displaystyle x=\frac{1\pm\sqrt{1+4\pi^{2}}}{2\pi}$ $x=1.17$ or $x=-0.85$

We are given: $\pi x^{2}-x-\pi=0$ $\pi x^{2}-1x-\pi=0$ We solve using the quadratic formula ($a=\pi,\ b=-1,\ c=-\pi$): $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ $x=\frac{-(-1)\pm\sqrt{(-1)^{2}-4*\pi*-\pi}}{2*\pi}$ $x=\frac{1\pm\sqrt{1+4\pi^{2}}}{2\pi}$ $x=1.17$ or $x=-0.85$