Answer
$\displaystyle x=\frac{-\pi\pm\sqrt{\pi^{2}+8\pi}}{2\pi}$
$x=0.44$ or $x=-1.44$
Work Step by Step
We are given:
$\pi x^{2}+\pi x-2=0$
We solve using the quadratic formula ($a=\pi,\ b=\pi,\ c=-2$):
$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$
$\displaystyle x=\frac{-\pi\pm\sqrt{(\pi)^{2}-4*\pi*-2}}{2*\pi}$
$\displaystyle x=\frac{-\pi\pm\sqrt{\pi^{2}+8\pi}}{2\pi}$
$x=0.44$ or $x=-1.44$
