Answer
$(x-8)(x-2)$
Work Step by Step
RECALL:
A trinomial of the form $x^2+bx+c$ can be factored if there are integers $d$ and $e$ such that $c=de$ and $b=d+e$.
The trinomial's factored form will be:
$x^2+bx+c=(x+d)(x+e)$
The given trinomial has $b=-10$ and $c=16$.
Note that $16=(-8)(-2)$ and $-10=(-8)+(-2)$.
This means that $d=-8$ and $e=-2$
Thus, the factored form of the trinomial is:
$=[x+(-8)] [x+(-2)]
\\=(x-8)(x-2)$
