College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.5 - Factoring Polynomials - R.5 Assess Your Understanding - Page 57: 50

Answer

$(x-16)(x-1)$

Work Step by Step

RECALL: A trinomial of the form $x^2+bx+c$ can be factored if there are integers $d$ and $e$ such that $c=de$ and $b=d+e$. The trinomial's factored form will be: $x^2+bx+c=(x+d)(x+e)$ The given trinomial has $b=-17$ and $c=16$. Note that $16=(-16)(-1)$ and $-17=(-16)+(-1)$. This means that $d=-16$ and $e=-1$ Thus, the factored form of the trinomial is: $=[x+(-16)] [x+(-1)] \\=(x-16)(x-1)$
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