Answer
$(x-8)(x+1)$
Work Step by Step
RECALL:
A trinomial of the form $x^2+bx+c$ can be factored if there are integers $d$ and $e$ such that $c=de$ and $b=d+e$.
The trinomial's factored form will be:
$x^2+bx+c=(x+d)(x+e)$
The given trinomial has $b=-7$ and $c=-8$.
Note that $-8=(-8)(1)$ and $-7=(-8)+1$.
This means that $d=-8$ and $e=1$
Thus, the factored form of the trinomial is:
$=[x+(-8)] (x+1)
\\=(x-8)(x+1)$
