Answer
$(x-2)(x+4)$
Work Step by Step
RECALL:
A trinomial of the form $x^2+bx+c$ can be factored if there are integers $d$ and $e$ such that $c=de$ and $b=d+e$.
The trinomial's factored form will be:
$x^2+bx+c=(x+d)(x+e)$
The given trinomial has $b=2$ and $c=-8$.
Note that $-8=(-2)(4)$ and $2=(-2)+4$.
This means that $d=-2$ and $e=4$
Thus, the factored form of the trinomial is:
$=[x+(-2)] (x+4)
\\=(x-2)(x+4)$
