Answer
$\dfrac{x+2}{x-2}; x \ne-2, 2$
Work Step by Step
Factor the numerator and the denominator completely to obtain:
$=\dfrac{(x+2)(x+2)}{(x-2)(x+2)}$
Cancel the common factors to obtain:
$\require{cancel}
\\=\dfrac{\cancel{(x+2)}(x+2)}{(x-2)\cancel{(x+2)}}
\\=\dfrac{x+2}{x-2}; x \ne-2, 2$
($x$ cannot be $-2$ and $2$ because they will make the original expression undefined.)
