Answer
$\dfrac{x+5}{x-1};x \ne 1$
Work Step by Step
Factor the numerator and the denominator completely to obtain:
$=\dfrac{(x+5)(x-1)}{(x-1)(x-1)}$
Cancel the common factors to obtain:
$\require{cancel}
\\=\dfrac{(x+5)\cancel{(x-1)}}{(x-1)\cancel{(x-1)}}
\\=\dfrac{x+5}{x-1};x \ne 1$
($y$ cannot be $1$ because it will make the original expression undefined.)
