Answer
$-x-3; x \ne \frac{1}{2}$
Work Step by Step
The given expression is equivalent to:
$=\dfrac{2x^2+5x-3}{-2x+1}$
Factor the numerator and the denominator completely to obtain:
$=\dfrac{(2x-1)(x+3)}{-(2x-1)}$
Cancel the common factors to obtain:
$\require{cancel}
\\=\dfrac{\cancel{(2x-1)}(x+3)}{-\cancel{(2x-1)}}
\\=\dfrac{x+3}{-1}
\\=-(x+3)
\\=-x-3; x \ne \frac{1}{2}$
($x$ cannot be $\dfrac{1}{2}$ because it will make the original expression undefined.)
