Answer
$-x-7, x \ne2$
Work Step by Step
The given expression is equivalent to:
$=\dfrac{x^2+5x-14}{-x+2}$
Factor the numerator and the denominator completely to obtain:
$=\dfrac{(x+7)(x-2)}{-(x-2)}$
Cancel the common factors to obtain:
$\require{cancel}
\\=\dfrac{(x+7)\cancel{(x-2)}}{-\cancel{(x-2)}}
\\=\dfrac{x+7}{-1}
\\=-(x+7)
\\=-x-7, x \ne2$
($x$ cannot be $2$ because it will make the original expression undefined.)
