College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.7 - Rational Expressions - R.7 Assess Your Understanding - Page 72: 77

Answer

$\frac{(x-1)(x+1)}{x(4x-2)}$

Work Step by Step

$\dfrac{2-\frac{x+1}{x}}{3+\frac{x-1}{x+1}}=\dfrac{\frac{2x}{x}-\frac{x+1}{x}}{\frac{3x+3}{x+1}+\frac{x-1}{x+1}}=\dfrac{\frac{x-1}{x}}{\frac{4x-2}{x+1}}=$$\frac{(x-1)(x+1)}{x(4x-2)}$
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