College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.7 - Rational Expressions - R.7 Assess Your Understanding - Page 72: 98

Answer

The LCM method is to be used whenever there is a common factor between the denominators as it will easily yield a reduced form.

Work Step by Step

The LCM method is to be used whenever there is a common factor between the denominators as it will easily yield a reduced form. Examples: a) Consider the example where LCM is used. $\dfrac{x-2}{(x-1)(x+2)}+\dfrac{3}{(x-1)^2}$ $=\dfrac{(x-2)(x-1)+3(x+2)}{(x-1)^2(x+2)}$ $=\dfrac{x^2-2x-x+2+3x+6}{(x-1)^2(x+2)}$ $=\dfrac{x^2+8}{(x-1)^2(x+2)}$ b) Consider the example where LCM is not needed. $\dfrac{x}{x-1}+\dfrac{2}{x-1}$ $=\dfrac{x+2}{x-1}$ Note that the denominators are already same.
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