Answer
$x^2y$
Work Step by Step
We use the rules of exponents and radicals to obtain:
$\displaystyle \sqrt[4]{\frac{x^{9}y^7}{xy^3}}=\sqrt[4]{x^{9-1}y^{7-3}}=\sqrt[4]{x^8y^4}=(x^{8}y^{4})^{1/4}=(x^{8})^{1/4}(y^{4})^{1/4}=x^2y^1=x^2y$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter R - Section R.8 - nth Roots; Rational Exponents - R.8 Assess Your Understanding - Page 78: 21
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