Answer
$3x^2y^3\sqrt[4]{2x}$
Work Step by Step
We use the rules of exponents and radicals to obtain:
$\displaystyle \sqrt[4]{162x^9y^{12}}=\sqrt[4]{81*2x^9y^{12}}=\sqrt[4]{3^42x^8xy^{12}}=3x^2y^3\sqrt[4]{2x}$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter R - Section R.8 - nth Roots; Rational Exponents - R.8 Assess Your Understanding - Page 78: 25
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