Answer
$-2x^4y^3\sqrt[3]{5x^2y}$
Work Step by Step
We use the rules of exponents and radicals to obtain:
$\displaystyle \sqrt[3]{-40x^{14}y^{10}}=\sqrt[3]{-8*5*x^{14}y^{10}}=\sqrt[3]{(-2)^{3}5x^{12}x^2y^{9}y}=-2x^4y^3\sqrt[3]{5x^2y}$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter R - Section R.8 - nth Roots; Rational Exponents - R.8 Assess Your Understanding - Page 78: 26
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