College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.8 - nth Roots; Rational Exponents - R.8 Assess Your Understanding - Page 78: 9

Answer

True

Work Step by Step

The statement is true because: $\sqrt[5]{-32}=\sqrt[5]{(-2)^5}=-2$
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