Answer
a.
$(\frac{5}{3})^{0}.2^{-1} = \frac{1}{2}$
b.
$\frac{2^{-3}}{3^{0}} = \frac{1}{8}$
c.
$(\frac{1}{4})^{-2} = 16 $
Work Step by Step
a.
$(\frac{5}{3})^{0}.2^{-1}$ = $1\times\frac{1}{2^{1}}$ = $\frac{1}{2}$
b.
$\frac{2^{-3}}{3^{0}} = \frac{1}{2^{3}\times3^{0}} = \frac{1}{8\times1} = \frac{1}{8}$
c.
$(\frac{1}{4})^{-2} = (\frac{1}{(\frac{1}{4})^{2}}) = (\frac{4}{1})^{2} = 16 $
