Answer
(a) $\frac{b^{3}}{3a}$
(b) $\frac{s^{3}}{q^{7}r^{4}}$
Work Step by Step
a) $(\frac{3a}{b^{3}})^{-1}$
$=\frac{b^{3}}{3a}$
b) $(\frac{q^{-1}r^{-1}s^{-2}}{r^{-5}sq^{-8}})^{-1}$
$=\frac{r^{-5}sq^{-8}}{q^{-1}r^{-1}s^{-2}}$
$=\frac{s^{3}}{q^{7}r^{4}}$