Answer
(a) $12x^4y^7$
(b) $\frac{x^7}{y}$
(c) $\frac{x^{6}y^{3}}{27}$
Work Step by Step
(a) $(2x^{2}y^{3})^{2}(3y)=2^{2}x^{2\cdot 2}y^{3\cdot 2} 3y=12x^{4}y^{7}$
(b) $\frac{x^{2}y^{-1}}{x^{-5}}=x^{2-(-5)}y^{-1}=x^{2+5}y^{-1}=x^{7}y^{-1}=\frac{x^7}{y}$
(c)$(\frac{x^{2}y}{3})^{3}=\frac{x^{2\cdot 3}y^{3}}{3^{3}}=\frac{x^{6}y^{3}}{27}$
