Answer
a. $\frac{1}{2}$
b. $\frac{1}{8}$
c. $2$
d. $8$
Work Step by Step
a. $2^{-1} = \frac{1}{2^{1}} = \frac{1}{2}$
b. $2^{-3} = \frac{1}{2^{3}} = \frac{1}{2\times2\times2} = \frac{1}{8}$
c. $(\frac{1}{2})^{-1} = \frac{1}{(\frac{1}{2})^{1}} =\frac{2}{1} = 2$
d. $\frac{1}{2^{-3}} = \frac{2^{3}}{1} = 2\times2\times2 = 8$