College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.6 - Factoring - P.6 Exercises - Page 42: 26

Answer

$(3a+4)(3a-4)$

Work Step by Step

Since $a^{2}-b^{2}=(a+b)(a-b)$, $9a^{2}-16=(3a+4)(3a-4)$.
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