Answer
$(x+3)(x^2-3x+9)$
Work Step by Step
RECALL:
$A^3+B^3=(A+B)(A^2-AB+B^2)$
The given binomial can be written as:
$x^3+3^3$
The binomial above is a sum of two cubes.
Factor using the the formula above with $A=x$ and $B=3$ to obtain:
$=(x+3)(x^2-x(3) + 3^2)
\\=(x+3)(x^2-3x+9)$
