Answer
$(y+3)^{2}$
Work Step by Step
Rearrange the terms of the trinomial.
$9+6y+y^{2}=y^{2}+6y+9$
Use the formula $a^{2}\pm2ab+b^2=(a\pm b)^{2}$ to factor the perfect square.
$y^{2}+6y+9=(y+3)^{2}$
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