Answer
$(x-y+3)(x+y+3)$
Work Step by Step
RECALL:
$A^2-B^2=(A-B)(A+B)$
Factor the difference of two squares using the formula above with $A=x+3$ and $B=y$ to obtain:
$=[(x+3)-y][(x+3)+y]
\\=(x+3-y)(x+3+y)
\\=(x-y+3)(x+y+3)$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter P, Prerequisites - Section P.6 - Factoring - P.6 Exercises - Page 42: 29
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