Chapter R - Section R.2 - Operations on Real Numbers - R.2 Exercises - Page 21: 104

$-\frac{10}{3}$

$\frac{12}{5}\div(-\frac{18}{25})=\frac{12}{5}\times-\frac{25}{18}=\frac{12\times-25}{5\times18}=\frac{-300}{90}=-\frac{300}{90}$ $-\frac{300}{90}=-\frac{300\div30}{90\div30}=-\frac{10}{3}$ The numbers being multiplied together have different signs, so the resulting product is negative.