Answer
$\frac{17}{18}$
Work Step by Step
$\frac{1}{6}-(-\frac{7}{9})=\frac{1}{6}+\frac{7}{9}=\frac{1\times3}{6\times3}+\frac{7\times2}{9\times2}=\frac{3}{18}+\frac{14}{18}=\frac{3+14}{18}=\frac{17}{18}$
Intermediate Algebra (12th Edition)
by Lial, Margaret L.; Hornsby, John; McGinnis, Terry
Published by
Pearson
ISBN 10:
0321969359
ISBN 13:
978-0-32196-935-4
Chapter R - Section R.2 - Operations on Real Numbers - R.2 Exercises - Page 21: 91
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