Answer
$\frac{35}{48}$
Work Step by Step
$-\frac{1}{12}+\frac{13}{16}=\frac{13}{16}-\frac{1}{12}=\frac{13\times3}{16\times3}-\frac{1\times4}{12\times4}=\frac{39}{48}-\frac{4}{48}=\frac{39-4}{48}=\frac{35}{48}$
Intermediate Algebra (12th Edition)
by Lial, Margaret L.; Hornsby, John; McGinnis, Terry
Published by
Pearson
ISBN 10:
0321969359
ISBN 13:
978-0-32196-935-4
Chapter R - Section R.2 - Operations on Real Numbers - R.2 Exercises - Page 21: 94
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