Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter R - Section R.2 - Operations on Real Numbers - R.2 Exercises - Page 21: 92

Answer

$\frac{13}{15}$

Work Step by Step

$\frac{7}{10}-(-\frac{1}{6})=\frac{7}{10}+\frac{1}{6}=\frac{7\times3}{10\times3}+\frac{1\times5}{6\times5}=\frac{21}{30}+\frac{5}{30}=\frac{21+5}{30}=\frac{26}{30}$ $\frac{26}{30}=\frac{26\div2}{30\div2}=\frac{13}{15}$
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