Answer
$-\frac{53}{45}$
Work Step by Step
$-\frac{11}{15}-\frac{4}{9}=-(\frac{11}{15}+\frac{4}{9})=-(\frac{11\times3}{15\times3}+\frac{4\times5}{9\times5})=-(\frac{33}{45}+\frac{20}{45})=-(\frac{33+20}{45})=-(\frac{53}{45})=-\frac{53}{45}$
Intermediate Algebra (12th Edition)
by Lial, Margaret L.; Hornsby, John; McGinnis, Terry
Published by
Pearson
ISBN 10:
0321969359
ISBN 13:
978-0-32196-935-4
Chapter R - Section R.2 - Operations on Real Numbers - R.2 Exercises - Page 21: 96
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