Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 1 - Linear Equations in Linear Algebra - 1.4 Exercises - Page 42: 26

Answer

Solution is$ \ \ x_1=2,x_2=-3$

Work Step by Step

The equation in $x_1$ and $x_2$ involves the vectors u, v, and w, and it may be viewed as $\left[\begin{array}{ l l }u&v\end{array}\right]\left[\begin{array}{ l }x_1\\x_2\end{array}\right]=w$ By definition of a matrix-vector product,$x_1u+x_2v=w$. The stated fact that 2u – 3v – w = 0 can be rewritten as 2u – 3v = w. So, a solution is$x_1=2,x_2=-3$
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