Answer
$\frac{(x)^2}{4}+\frac{y^2}{9}=1$ and Foci: $( 0,\pm \sqrt 5 )$
Work Step by Step
From the figure, major axis: $a=3$ and minor axis: $b=2$
Therefore, $\frac{(x)^2}{4}+\frac{y^2}{9}=1$
$c^2=a^2-b^2=9-4=5$
$c=\sqrt 5$
Hence, $\frac{(x)^2}{4}+\frac{y^2}{9}=1$ and Foci: $( 0,\pm \sqrt 5 )$
