Answer
$\frac{y^{2}}{4}-\frac{x^{2}}{21}=1$
Work Step by Step
Here, $a=2$ and $c=5$ from the given points
we can write
$5^2=2^2+b^2$
$25-4=b^2$
$b^2=21$
The equation of the hyperbola is
$\frac{y^{2}}{4}-\frac{x^{2}}{21}=1$
Multivariable Calculus, 7th Edition
by Stewart, James
Published by
Brooks Cole
ISBN 10:
0-53849-787-4
ISBN 13:
978-0-53849-787-9
Chapter 10 - Parametric Equations and Polar Coordinates - 10.5 Exercises - Page 700: 44
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