Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 10 - Parametric Equations and Polar Coordinates - 10.5 Exercises - Page 700: 43

Answer

$\frac{x^{2}}{9}-\frac{y^{2}}{16}=1$

Work Step by Step

Here, $a=3$ and $c=5$ from the given points we can write $5^2=3^2+b^2$ $25-9=b^2$ $b^2=16$ The equation of the hyperbola is $\frac{x^{2}}{9}-\frac{y^{2}}{16}=1$
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