Answer
$(x-3)^2=16(y-2)$
Work Step by Step
Distance of the point $(x,y)$ from the line $y=2$ is $|y+2|$
Therefore, the equation of the parabola is
$|y+2|=\sqrt {(x-3)^2+(y-6)^{2}}$
$(x-3)^2=16y-32$
$(x-3)^2=16(y-2)$
Multivariable Calculus, 7th Edition
by Stewart, James
Published by
Brooks Cole
ISBN 10:
0-53849-787-4
ISBN 13:
978-0-53849-787-9
Chapter 10 - Parametric Equations and Polar Coordinates - 10.5 Exercises - Page 700: 34
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