Answer
Parabola
Foci: $( \frac{3}{2},4)$
Vertices : $(0,4)$
Work Step by Step
$y^{2}-8y+16-16=6x-16$
$(y-4)^2=6x$, equation of parabola
$4p=6$
$p=\frac{3}{2}$
Foci: $( \frac{3}{2},4)$
Vertices : $(0,4)$
Multivariable Calculus, 7th Edition
by Stewart, James
Published by
Brooks Cole
ISBN 10:
0-53849-787-4
ISBN 13:
978-0-53849-787-9
Chapter 10 - Parametric Equations and Polar Coordinates - 10.5 Exercises - Page 700: 28
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