Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 1: Functions - Section 1.1 - Functions and Their Graphs - Exercises 1.1 - Page 12: 28

Answer

The first part of the graph is $\frac{1}{x}$ between both asymptotes x=0 and y=0. The second part of the graph is the linear graph x from (0,0) on.

Work Step by Step

$G(0) = \frac{1}{0}$, which is impossible. So x = 0 is an asymptote of $\frac{1}{x}$. The other asymptote of $\frac{1}{x}$ is y = 0, which is obtained by substituting a very big negative value of x. Thus the first part of the graph will be $\frac{1}{x}$ between both asymptotes x=0 and y=0. $G(0) = {0}$ $G(1) = {1}$ So the second part of the graph will be the linear graph x from (0,0) on.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.