Answer
The function is even.
Work Step by Step
$h(t)=|t^3|$
$h(-t)=|(-t)^3|=|t^3|$
$-h(t)=-|t^3|$
$h(t)=h(-t)$ - The function is even.
$h(-t)\neq -h(t)$ - The function is not odd.
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 1: Functions - Section 1.1 - Functions and Their Graphs - Exercises 1.1 - Page 12: 56
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