Answer
The function is odd.
Work Step by Step
$g(x)=\frac{x}{x^2-1}$
$g(-x)=\frac{-x}{(-x)^2-1}=-\frac{x}{x^2-1}$
$-g(x)=-\frac{x}{x^2-1}$
$g(x)\neq g(-x)$ - The function is not even.
$g(-x)= -g(x)$ - The function is odd.
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 1: Functions - Section 1.1 - Functions and Their Graphs - Exercises 1.1 - Page 12: 54
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