Answer
The function is odd.
Work Step by Step
$g(x)=x^3+x$
$g(-x)=(-x)^3-x=-x^3-x$
$-g(x)=-x^3-x$
$g(x)\ne g(-x)$ - The function is not even.
$g(-x)=-g(x)$ The function is odd.
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 1: Functions - Section 1.1 - Functions and Their Graphs - Exercises 1.1 - Page 12: 51
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