University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 1 - Section 1.2 - Combining Functions; Shifting and Scaling Graphs - Exercises - Page 19: 21

Answer

The equation of the yellow graph is $$y = -(x+7)^2$$ The equation of the red graph is: $$y = -(x-4)^2$$

Work Step by Step

The blue graph is the graph of function $y = -x^2$. It collides with the x-axis at point $x = 0$. 1) First, we look at the yellow graph: - It is a horizontal shift. So the equation of the function of yellow graph has this form: $$y = -(x + h)^2$$ - The yellow graph shifts to the left of the blue graph, so $h\gt0$. - The yellow graph collides with the x-axis at point $x=-7$, which is $7$ units away from the blue graph, so $|h|=7$. - Since we know that $h\gt0$, we figure that $h=7$ Therefore, the equation of the yellow graph is: $$y = -(x+7)^2$$ 2) Now, about the red graph: - It is also a horizontal shift. So the equation of the function of the red graph also has this form: $$y = -(x + h)^2$$ - However, since the red graph shifts to the right of the blue graph, we figure that $h\lt0$. - The red graph collides with the x-axis at point $x=4$, which is $4$ units away from the blue graph, so $|h|=4$. - Yet, because $h\lt0$, we conclude that $h=-4$ Therefore, the equation of the red graph is: $$y = -(x-4)^2$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.