University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 1 - Section 1.2 - Combining Functions; Shifting and Scaling Graphs - Exercises - Page 19: 22

Answer

The equation of the red graph is: $$y = x^2+3$$ The equation of the yellow graph is: $$y = x^2-5$$

Work Step by Step

The blue graph is the graph of function $y = x^2$. It collides with the y-axis at point $y = 0$. 1) First, we look at the yellow graph: - It is a vertical shift. So the equation of the yellow graph has this form: $$y = x^2+h$$ - The yellow graph shifts to below the blue graph, so $h\lt0$. - The yellow graph collides with the y-axis at point $y=-5$, which is $5$ units away from the blue graph, so $|h|=5$. - Since we know that $h\lt0$, we figure that $h=-5$ Therefore, the equation of the yellow graph is: $$y = x^2-5$$ 2) Now, about the red graph: - It is a vertical shift. So the equation of the red graph has this form: $$y = x^2+h$$ - The red graph shifts to above the blue graph, so $h\gt0$. - The red graph collides with the y-axis at point $y=3$, which is $3$ units away from the blue graph, so $|h|=3$. - Since we know that $h\gt0$, we figure that $h=3$ Therefore, the equation of the red graph is: $$y = x^2+3$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.