Answer
$$\lim_{\theta\to0}\frac{\sin\theta}{\sin2\theta}=\frac{1}{2}$$
Work Step by Step
$$\lim_{\theta\to0}\frac{\sin\theta}{\sin2\theta}=\lim_{\theta\to0}\frac{\sin\theta}{2\sin\theta\cos\theta}$$
$$\lim_{\theta\to0}\frac{\sin\theta}{\sin2\theta}=\lim_{\theta\to0}\frac{1}{2\cos\theta}$$
$$\lim_{\theta\to0}\frac{\sin\theta}{\sin2\theta}=\frac{1}{2\cos0}$$
$$\lim_{\theta\to0}\frac{\sin\theta}{\sin2\theta}=\frac{1}{2\times1}=\frac{1}{2}$$