Answer
$(3x-5)(x+1)$
Work Step by Step
$3x^{2}-2x-5=$
two factors of $ac=-15$ whose sum is $b=-2$ are $-5$ and $+3.$
Rewrite the middle term and factor in pairs.
$3x^{2}-2x-5=3x^{2}-5x+3x-5$
$=x(3x-5)+(3x-5)$
$=(3x-5)(x+1)$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter P - Section P.5 - Factoring Polynomials - Exercise Set - Page 68: 26
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