Answer
$(8x+1)(x+4)$
Work Step by Step
$8x^{2}+33x+4=$
two factors of $ac=+32$ whose sum is $b=+33$ are $+32$ and $+1.$
Rewrite the middle term and factor in pairs.
$8x^{2}+33x+4=8x^{2}+32x+x+4$
$=8x(x+4)+(x+4)$
$=(8x+1)(x+4)$
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