Answer
$(2x+3)(2x+5)$
Work Step by Step
$4x^{2}+16x+15=$
two factors of $ac=+60$ whose sum is $b=+16$ are $+6$ and $+10.$
Rewrite the middle term and factor in pairs.
$4x^{2}+16x+15=4x^{2}+6x+10x+15$
$=2x(2x+3)+5(2x+3)$
$=(2x+3)(2x+5)$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter P - Section P.5 - Factoring Polynomials - Exercise Set - Page 68: 29
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