Answer
$(3x-5y)(2x+y)$
Work Step by Step
$6x^{2}-7xy-5y^{2}=$
two factors of $ac=-30$ whose sum is $b=-7$ are $-10$ and $+3.$
Rewrite the middle term and factor in pairs.
$6x^{2}-7xy-5y^{2}=6x^{2}-10xy+3xy-5y^{2}$
$=2(3x-5y)+(3x-5y)$
$=(3x-5y)(2x+y)$