Answer
$(3x-2)(5x-3)$
Work Step by Step
$15x^{2}-19x+6=$
two factors of $ac=+90$ whose sum is $b=-19$ are $-10$ and $-9.$
Rewrite the middle term and factor in pairs.
$15x^{2}-19x+6=15x^{2}-10x-9x+6=$
$=5x(3x-2)-3(3x-2)$
$=(3x-2)(5x-3)$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter P - Section P.5 - Factoring Polynomials - Exercise Set - Page 68: 34
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